求yi路向xi2一路向西完整版观看?

电影《yi路向西2之泰西》哪里有啊?求个完整_百度知道
电影《yi路向西2之泰西》哪里有啊?求个完整
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File Name :
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File Size :2003947 byte
File Type :application/x-dosexec
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Scanner results:<font color="#%Scanner(s) (4/39)found malware!
Time: <font color="#14-09-08 22:47:51 (CST)
Engine Ver
Scan result
Found nothing
7.11.171.32
Found nothing
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9.0.0.4157
9.0.0.4157
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4.1.3.52192
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Found nothing
bitdefender
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Found nothing
5.0.2.3300
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22.765, 22.765
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6.5.1.5418
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V1.32.31.0
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9.500-1005
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25.17.00.04
25.17.00.04
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Found nothing
3.9.2589.2
3.9.2589.2
Found nothing
Found nothing
Found nothing
Found nothing
17.47.17308
1.0.2.2108
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virusbuster
15.0.901.0
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You can view the results of the last scan or rescan若X1,X2…Xn为来自N(0,σ2)的样本;.X为样本均值,Yi=Xi-.X,i=1,2…n,求:(1)Yi的方差;(2)Cov(Y1,Yn).(3)当a为何值时,F=aX21X22+X23+…+X2n服从F分布?_作业帮
拍照搜题,秒出答案
若X1,X2…Xn为来自N(0,σ2)的样本;.X为样本均值,Yi=Xi-.X,i=1,2…n,求:(1)Yi的方差;(2)Cov(Y1,Yn).(3)当a为何值时,F=aX21X22+X23+…+X2n服从F分布?
若X1,X2…Xn为来自N(0,σ2)的样本;为样本均值,Yi=Xi-,i=1,2…n,求:(1)Yi的方差;(2)Cov(Y1,Yn).(3)当a为何值时,F=服从F分布?
(1)由题意可知,i-ni=1Xin]=i-1nnj≠iXj],因为Xi,Xj为随机抽样的样本,所以两者不相关.所以上式=2D(Xi)+1n2nj≠iD(Xj)=2+1n2(n-1)σ2=n-1nσ2(2)Cov(Y1,Yn)=E{[Y1-E(Y1)][Yn-E(Yn)]},其中E(Y1)=E(Yn)=0,所以Cov(Y1,Yn)=E(Y1Yn)=1-.X)(Xn-.X)]=1Xn-X1.X-Xn.X+.X2)=1Xn)-E(X1.X)-E(Xn.X)+E(.X2)对于任意的i,有i.X)=E(Xi1nn<t
本题考点:
F分布的概率密度函数及曲线.
问题解析:
(1)随机抽样的样本独立同分布,每个不同的样本之间不相关.所以可以将Yi拆成Xi和与Xi不相关的统计量,这样计算方差和期望都更加简便;(2)利用协方差的定义求解,因为Yi并不是特殊的分布,所以将Yi转化为Xi有关的代数式,利用正态分布的相关性质求解;(3)理解F分布的定义,观察分子、分母,将分子、分母和标准正态分布的和联系起来,得出F分布的形式,与带有参数的式子比较可得a的值.=2)是正太分布N(μ,σ^2)的一个样本,若统计量{i=1到n-1}范围内KΣ[X(i+1)-Xi]^2为σ^2的无偏估计,则K的值应该为多少?求解题思路.X(i+1)-Xi里面的i+1和i都是下标">
设X1、X2、……、Xn(n>=2)是正太分布N(μ,σ^2)的一个样本,若统计量{i=1到n-1}范围内KΣ[X(i+1)-Xi]^2为σ^2的无偏估计,则K的值应该为多少?求解题思路.X(i+1)-Xi里面的i+1和i都是下标_作业帮
拍照搜题,秒出答案
设X1、X2、……、Xn(n>=2)是正太分布N(μ,σ^2)的一个样本,若统计量{i=1到n-1}范围内KΣ[X(i+1)-Xi]^2为σ^2的无偏估计,则K的值应该为多少?求解题思路.X(i+1)-Xi里面的i+1和i都是下标
设X1、X2、……、Xn(n>=2)是正太分布N(μ,σ^2)的一个样本,若统计量{i=1到n-1}范围内KΣ[X(i+1)-Xi]^2为σ^2的无偏估计,则K的值应该为多少?求解题思路.X(i+1)-Xi里面的i+1和i都是下标
K要使这个表达式的期望值为σ^2求期望时可以用E[X(i+1)-Xi]^2=E[(X(i+1)-μ)-(Xi-μ)]^2=E[(X(i+1)-μ)^2+(Xi-μ)^2-2(X(i+1)-μ)(Xi-μ)]=σ^2+σ^2-2*0*0交叉项用到了样本的独立性.接下去就很容易了.K=1/2(n-1)}

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